[Linux OT] Regular expresion question

[Jesus Antonio Santos Giraldo]

.9 match any char and a '9' literally, of course, I don't know what I was
thinking...

For what I've seen, I think I'm trying to force REs beyond their scope.


Chucho!

>The ".9" specifies September.  The '.' matches any single character, while
the
>9 matches literally.  Since the only candidates are going to be 09,
>this does the
>trick.  To match just November, you'd have to use "11", because ".1" would
match
>both January (01) and November(11), while "1." would match 10, 11 and 12.
>
>Number ranges are a bit hard in regular expressions because REs are not
>designed for any numeric interpretation at all.  They are purely text
matches.
>Character ranges like [0-5] can help, but they are not the same thing.
>
>++ kevin
>
>On Tue, 05 Oct 2004 05:37:16 -0500, Jean Sagi <jeansagi at uniweb.net.co>
wrote:
>> 
>> You example works for the case I give. Thanks.
>> 
>> I didn't understand ".9" in the patterns you gave; what they are used
for?
>> 
>> The pattern works with them and without them, I mean the next statement
>> works the way I want:
>> 
>>    [chucho at oolnta hist]$ ls | grep -e "^h1[0-9].9" -e "^h2[0-5].9"
>>    h100904
>>    h120904
>>    h130904
>>    h180904
>>    h200904
>>    h240904
>>    h250904
>> 
>>    [chucho at oolnta hist]$ ls | grep -e "^h1[0-9]" -e "^h2[0-5]"
>>    h100904
>>    h120904
>>    h130904
>>    h180904
>>    h200904
>>    h240904
>>    h250904
>> 
>> Finally I wonder if there is a more generic way of handling ranges with
>> regular expresions, or maybe I'm trying to use the way they are not
>> meant to.
>> 
>> Chucho!
>> 
>> 
>> 
>> Brad De Vries wrote:
>> > Jean, you could try sed using the following syntax:
>> > $ sed -n -e "/^h1[0-9].9/p" -e "/^h2[0-5].9/p"
>> >
>> >
>> 
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>> 
>
>
>-- 
>Go back to the top: I almost always top-post
>Kevin O'Gorman, PhD
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