bash case statement question

[David A. Bandel]

On Thu, Sep 22, 2011 at 00:59, Roger Oberholtzer <roger at opq.se> wrote:
> On Wed, 2011-09-21 at 10:51 -0700, xDog Walker wrote:
>> Here is a question about bash: What does the .$1 mean in the following case
>> statement (I know $1 means the first argument, but what does the . mean
>> here?)
>>
>>      case .$1 in
>>
>> and later on:
>>
>>      .[aA])
>>            SAMPLE="blah";;
>
> I suspect it is in case $1 is not set. Then there is still something in
> the case statement (e.g., "case . in"). Without this, the case statement
> will fail. Another method is to only do the case statement if you first
> determine that $1 has been assigned a value.

actually, *) would take care of the case where $1 isnull, but he need
".*" to account for the dot.

>
> Since this '.' has been added to the case part. it also has to be in all
> the .XXX) parts as well. Any ASCII printable character would work.
>
> Yours sincerely,
>
> Roger Oberholtzer
>
> OPQ Systems / Ramböll RST
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Ciao,

David A. Bandel
-- 
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