C Programming question ...

[Steve Jardine]

Kevin is right. No declaration. But, a symbol is created that is used for creating a 
pointer to memory of the appropriate size upon declaration.

typedef struct  is_field field_t; <<== Messy...

Why not:
 typedef struct {
        int     f_type;
        int     f_size;
        int     f_offset;
        char    f_name[MAXFIELDNAME];
} is_field;

is_field xyz;

xyz.f_size=16384; etc...

Steve


On Wed, 7 Jan 2009 08:55:46 -0800
"Kevin O'Gorman" <kogorman at gmail.com> wrote:

> On Wed, Jan 7, 2009 at 8:00 AM, Ben Duncan <bend at linux4ms.net> wrote:
> > On this example:
> >
> > struct  is_field {
> >        int     f_type;
> >        int     f_size;
> >        int     f_offset;
> >        char    f_name[MAXFIELDNAME];
> > };
> > typedef struct  is_field field_t;
> >
> >
> > Is the "typedef item field_t" being allocated or just declared?
> >
> > I know if I do a :
> >
> > struct is_field {
> >  ......         } My_Struct
> >
> > then My_Struct is allocated
> >
> >
> > Thanks ...
> 
> The typedef does not declare a thing, but a type.  You can then use the type
> to declare (and possibly allocate) things.  In this case, the new type
> is field_t.
> So you can use it in a declarations
>     field_t fieldThing;
> Which I woruld prefer to the awkward alternative
>     struct is_field otherThing;
> 
> HTH
> 
> ++ kevin
> 
> >
> > --
> > Ben Duncan - Business Network Solutions, Inc. 336 Elton Road  Jackson MS,
> > 39212
> > "Never attribute to malice, that which can be adequately explained by
> > stupidity"
> >       - Hanlon's Razor
> >
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> >
> 
> 
> 
> -- 
> Kevin O'Gorman, PhD
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