bedtime question : xargs

[David A. Bandel]

On Wed, Apr 22, 2009 at 10:59 PM, Vu Pham <vu at sivell.com> wrote:
> Using xargs, how can I pipe the output ( of some command ) as the *first*
> parameter of some other command ?
>
> Here is my problem: I have various rpm files in a directory tree. I want to
> copy all of these files to a remote server using scp. What I am thinking is
>
> [oliver at xen2vm4 redhat]$ find . -name "*.rpm"
> ./SRPMS/hello-1.0.0-2.src.rpm
> ./SRPMS/hello-1.0.0-1.src.rpm
> ./RPMS/i686/hello-1.0.0-2.i686.rpm
> ./RPMS/i686/hello-1.0.0-1.i686.rpm
>
>
> # find . -name "*.rpm" | xargs  scp  ???   root at remoteserver:

why invoke xargs at all?
find . -name \*.rpm -exec scp {} root at remoteserver: \;
(note:  the \; is required)

>
> How can I make each of the line to be set into the ??? of scp ?
> I do not care if the directory tree is created or not on the remote server
>
> Or am I doing something too complicated ?


David A. Bandel
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