List of users from command line

[Brad De Vries]

On Mon, 3 Jan 2005 11:30:55 -0500, David Bandel <david.bandel at gmail.com> wrote:
> On Mon, 03 Jan 2005 10:20:15 -0500, Matthew Carpenter <matt at eisgr.com> wrote:
> > -----BEGIN PGP SIGNED MESSAGE-----
> > Hash: SHA1
> >
> > # getent passwd
> 
> if you only want user accounts, and they're all between 500-999:
> getent passwd | cut -f1,3 -d: - | grep [5-9].. - | cut -f1 -d: -
> add -v to the grep to get system accounts
> 
> likewise, if your user accounts are 1000+ use:
> getent passwd | cut -f1,3 -d: - | grep [1-9]... - | cut -f1 -d: -
> 
> The above can be refined even more, but that should give you the idea.
> 
> There are similar tricks to get lists of those with null passwords, etc.
> 
> >
> > This should work for virtually any form of authentication you use.  This
> > has been tested and proven with compat, LDAP and Winbind
> > Chong Yu Meng wrote:
> > | Hi All,
> > |
> > | Another elementary question for the gurus on this list :
> > |
> > | I need to get a list of user accounts on a server, and though I know I
> > | can probably do it using webmin or graphical tools, I am specifically
> > | looking for a command that will do this for me. Can someone help?
> > |
> > | Thanks in Advance !
> 
> Ciao,
> 
> David A. Bandel
> --
> Focus on the dream, not the competition.
>             - Nemesis Air Racing Team motto

Or, if you like awk, you could use:
getent passwd | awk -F: '{if (($3 >= 500) && ($3 <= 999)) {print $1}}'

This will provide the user name only.  If you'd like to see the real
name as well (with a tab separator,) change the print command to
{print $1,"\t",$5}

Brad.