Joel Hammer wrote: > I understand that bash will do arithmetic in octal if you prefix the > constant with 0. So: > a=05 > b=017 > c=$((a*b)) > echo $c > yields > 75 > This is the correct answer, but it is in decimals, not octals. > Is there a way to make echo display octal? > Thanks, > Joel > More arithmetic? echo $((8#$c*1)) gives 61 Tom Wekell