Bash scripting question

[Roger Oberholtzer]

# This should echo command line parameters (or function paramaeters if
# placed in a shell function), one per line.


for param in $*
do
	echo $param
done


On Mon, 26 May 2003 21:45:32 -0700
David Aikema <dhaikema at sfu.ca> wrote:

> I'm trying to loop through all of the command line parameters passed to 
> a bash script.
> 
> I know that $# is the total number of
> command line options passed (well, $#+1 if you include $0, the name of the
> script) and that the individual parameters can be access as $0, $1, $2,
> and so on.
> 
> How can I loop through all of the given parameters though?
> 
> for ((NUM=1; NUM <= $#; NUM++))
> do
> 	# what?
> 	#how can I access parameter # NUM?
> done
> 
> David Aikema
> 
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