GCC oddity

[Kevin O'Gorman]

I have a short program that provokes an error when compiled on
some versions of gcc, and I cannot figure out why.  I'm using
the stock gcc that came with RedHat 7.1 (gcc 2.96-81)

The program is simple:
##################### CUT HERE ###################################
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>

int
main(){
        int r;
        struct stat buf;

        r = lstat(".", &buf);
        return r;
}
##################### CUT HERE ###################################

And I use a simple makefile:

##################### CUT HERE ###################################
CC =gcc
CFLAGS = -g -Wall -ansi -pedantic

foo: foo.c

bar.c: foo.c
        gcc -E $< | perl -p -e 's:(#.*):/* \1 */:' >$@

clean:
        rm bar* foo.o foo
##################### CUT HERE ###################################

If I use the command 'make foo' I get

> gcc -g -Wall -ansi -pedantic    foo.c   -o foo
> foo.c: In function `main':
> foo.c:10: warning: implicit declaration of function `lstat'

But I don't get this warning if I use the preprocessor to
make a source file without includes.  This should be identical
to the results for foo.c, but if I use the command 'make bar'
I get:

> gcc -E foo.c | perl -p -e 's:(#.*):/* \1 */:' >bar.c
> gcc -g -Wall -ansi -pedantic    bar.c   -o bar

I had expected the same error with the constructed bar.c, so that
I could narrow down the cause of the error, but this is quite
frustrating.

Any ideas?

++ kevin