Fw: Re: Network Address/Netmask Notation

[Vern W Heesch]

Ugg, forget that. It was too early to think. What I gave was for x.x.x.x/16

Begin forwarded message:

Date: Sun, 23 Mar 2003 08:09:23 -0800
From: Vern W Heesch <vheesch at qwest.net>
To: linux-users at linux-sxs.org
Subject: Re: Network Address/Netmask Notation


You are correct that the first 2 octets are for network number, which leaves the last 2 octets for hosts. So the range of useable host addresses are 192.168.0.1 - 192.168.255.254 with a netmask of 255.255.0.0

On Sun, 23 Mar 2003 10:54:54 -0500
"Kurt Wall" <kwall at kurtwerks.com> wrote:

> Hi, list,
> 
> I've never been terribly clear on this, so I'll ask here. Given
> a network address of, say, 192.168.0.0 and a netmask of /8, thus
> 192.168.0.0/8, this means that 8 bits of the network address will
> be used for the host address, which means that any address in the
> range 192.168.0.1 - 192.168.0.255 will match. Am I correct?
> 
> Thanks,
> 
> Kurt
> -- 
> "When you are in it up to your ears, keep your mouth shut."
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