Bash: Variable type confusion

[Joel Hammer]

What version of bash are you using?

I have having a lot of trouble with variable typing.
My version of bash is:
GNU bash, version 2.04.0(1)-release (i686-pc-linux-gnu)
Copyright 1999 Free Software Foundation, Inc.   


Joel


On Sun, Oct 20, 2002 at 02:23:16PM -0700, Net Llama! wrote:
> On 10/20/02 13:53, Joel Hammer wrote:
> 
> > I have always thought that bash does the right thing when it evaluates
> > variables.
> > Until today.
> > This bit of script works as expected:
> > k=0
> > for i in `dir -1 *jpg`
> > do
> > k=$((k+1))
> > echo $k
> > done
> >
> > It prints out the numbers from 1 to whatever the number of jpg's in the
> > directory.
> >
> > However, this fails:
> > k=0
> > for i in `dir -1 *jpg`
> > do
> > k=$((k+1))
> > [ "$k" -eq 10 ] && k=x   <---The problem.
> > echo $k
> > done
> 
> Both of these work the same for me, using bash.
> 
> -- 
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> L. Friedman                       	       netllama at linux-sxs.org
> Linux Step-by-step & TyGeMo: 		    http://netllama.ipfox.com
> 
>    2:20pm  up 8 days,  2:38,  1 user,  load average: 0.11, 0.40, 0.41
> 
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